If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2b^2-4b-96=0
a = 2; b = -4; c = -96;
Δ = b2-4ac
Δ = -42-4·2·(-96)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-28}{2*2}=\frac{-24}{4} =-6 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+28}{2*2}=\frac{32}{4} =8 $
| 9m+8=4m+43 | | c/6+71=79 | | -10=k+2 | | 2(g-1)+7=2g+5 | | 6y-15=3+2y | | 5+2t=4t=6 | | 11-2r=15 | | 8-23x=5 | | 95×+98x=2,895 | | 4x+7/8=1 | | 6.2(x+4)=86.8 | | 6-5x=2x^ | | 4y+5=20-2y | | −23x−34=−54 | | 12v^2-58v+56=0 | | u/3+45=52 | | 9s+7=43 | | 7x+14=-147 | | 3a^2-45a+162=0 | | 3(x-6)=2(x=3)+6 | | r=-12=6 | | 4x+6(24)=96 | | r-12=9 | | 3/4x^2-4x+10/3=0 | | 15-1,6n=1,6n-1 | | 10x+16=96 | | q^2*(16q^2-8+1)=0 | | 3x+14+5x-2+10x=18 | | (x+2)/4=(2x-5)/2 | | 36y+8=18 | | -25=r3-11 | | q^2(16q^2-8+1)=0 |